Respuesta :
"5 times square root 61 over 61" is the one among the following choices given in the question that is the sine value of this function. The correct option among all the options that are given in the question is the first option or option "A". hope that this is the answer that has come to your great help.
By definition, the sine of an angle is given by:
[tex]sin \alpha = \frac{C.O}{h} [/tex]
Where,
C.O: opposite leg
h: hypotenuse
The hypotenuse is given by:
[tex]h = \sqrt{(-6)^2+(5)^2} [/tex]
[tex]h = \sqrt{(61} [/tex]
So, replacing values we have:
[tex]sin \alpha = \frac{5}{\sqrt{61}}[/tex]
Rewriting we have:
[tex]sin \alpha = \frac{5\sqrt{61}}{61}[/tex]
Answer:
the sine value of this function is:
A)5 times square root 61 over 61
[tex]sin \alpha = \frac{C.O}{h} [/tex]
Where,
C.O: opposite leg
h: hypotenuse
The hypotenuse is given by:
[tex]h = \sqrt{(-6)^2+(5)^2} [/tex]
[tex]h = \sqrt{(61} [/tex]
So, replacing values we have:
[tex]sin \alpha = \frac{5}{\sqrt{61}}[/tex]
Rewriting we have:
[tex]sin \alpha = \frac{5\sqrt{61}}{61}[/tex]
Answer:
the sine value of this function is:
A)5 times square root 61 over 61