Question

The density of magnesium is 1.7 g/cm3, and the density of iron is 7.9 g/cm3. Consider a block of iron with a mass of 819 g. What is the mass of a block of magnesium that has the same volume as the block of iron?

Answer 1

Answer:

mass of Mg=0.016g

Explanation:

P(Mg)=1.7g/cm³

P(Fe)=7.9g/cm³

m(Fe)=819g

P(Fe)=m(Fe)/v(Fe)

7.9=819/v(Fe)

v(Fe)=0.0096cm³

since v(Mg)=v(Fe)

=0.0096cm³

P(Mg)=m(Mg) /v(Mg)

1.7=m(Mg)/0.0096

m(Mg) = 0.016g

Answer 2

The mass of the Mg block has been found to be 176.24 grams.

The density can be defined as the mass per unit volume. The density can be expressed as:

Density = $\rm \dfrac{Mass}{Volume}$

The volume of the object will be:

Volume = $\rm \dfrac{Mass}{Density}$

The density of Mg block = 1.7 g/$\rm cm^3$

The density of Fe block = 7.9 g/$\rm cm^3$.

Since the volume of both blocks has been the same.

$\rm \dfrac{Mass\;of\;Mg\;block}{Density\;of\;Mg\;block}\;=\;\dfrac{Mass\;of\;Fe\;block}{Density\;of\;Fe\;block}$

The given mass of Fe block = 819 g.

Substitute the values:

$\rm \dfrac{Mass\;of\;Mg\;block}{1.7\;g/cm^3}\;=\;\dfrac{819\;g}{7.9\;g/cm^3}$

Mass of Mg block = 176.24 g.

The mass of the Mg block has been found to be 176.24 grams.

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