Question

SUPER URGENT Sam is eating a Big Hamburger. The first bite was 20% of the Hamburger, the second bite was 20% of what is left and so every next bite is 20% of what is left.


Is it possible for Sam to eat it all if he will bite 20% of what it is left?

Answer 1

No, Sam will not be able to finish the large hamburger if he only bites 20% of what is left.

What is the percentage?

In mathematics, a percentage is defined as a figure or ratio expressed as a fraction of 100. The percent sign, "%," is commonly used to indicate it.

How to solve this problem?

Let the size of the hamburger be 100 units.

Here, the first bite was 20% of the hamburger.

So the remaining portion of the hamburger is 100 - (100*(20/100)) = 80 units.

The second bite was 20% of 80%. Again the remaining portion is 80 - (80*(20/100)) = 80 - 16 = 64 units.

After the third bite, the remaining portion is 64 - (64*(20/100)) = 64 - 12.8 = 51.2 units.

After the fourth bite, the remaining portion is 51.2 - (51.2*(20/100)) = 51.2 - 10.24 = 40.96 units.

After the fifth bite, the remaining portion is 40.96 - (40.96*(20/100)) = 40.96 - 8.192 = 32.768 units.

...

Since the criterion is Sam will bite 20% of what is left, this remaining portion is never zero. It will always be a fraction like 0.00000000000001. Again we have to find 20% of 0.00000000000001 and subtract it from 0.00000000000001. So, It will continue.

Therefore, we can conclude that it is not possible for Sam to eat the big hamburger all if he will bite 20% of what is left.

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