Question

A bowl of cold gazpacho soup is warming to room temperature.the temperature difference between the soup and the room decreases by 5% every minute. What will the temperature difference be in 5 minutes if it is currently 16°C

Answer 1

Answer:

The temperature difference in 5 minutes will be 12.38ºC

Step-by-step explanation:

The difference in temperature after t minutes is given by the following equation:

$T(t) = T(0)(1-r)^{t}$

In which T(0) is the initial temperature and r is the decrease rate, as a decimal.

Decreases by 5% every minute.

This means that $r = 0.05$

What will the temperature difference be in 5 minutes if it is currently 16°C

This is T(5) when $T(0) = 16$

So

$T(t) = T(0)(1-r)^{t}$

$T(t) = 16(1-0.05)^{t}$

$T(t) = 16*(0.95)^{t}$

$T(5) = 16*(0.95)^{5} = 12.38$

The temperature difference in 5 minutes will be 12.38ºC