Question

A circle is centered at O(0,0)O(0,0)O, left parenthesis, 0, comma, 0, right parenthesis and has a radius of \sqrt{29}


29


​


square root of, 29, end square root.


Where does the point T(5,-2)T(5,−2)T, left parenthesis, 5, comma, minus, 2, right parenthesis lie?

Answer 1

Answer:

Point T is on the circle

Step-by-step explanation:

To check where the point lies, we need to find its distance to the center of the circle.

The distance between two points (x1, y1) and (x2, y2) is given by:

$distance = \sqrt[2]{(x2 - x1)^{2} + (y2 - y1)^{2}}$

If the first point is O(0,0) and the second is T(5, -2), we have:

$distance = \sqrt[2]{(5 - 0)^{2} + (-2 - 0)^{2}}$

$distance = \sqrt{29}$

The distance between the points is equal the radius of the circle, that means the point T is on the circle.

Answer 2

Answer:

inside the circle

Step-by-step explanation:

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