Answer:
Total paper required = 165 cm²
Step-by-step explanation:
Paper required to cover the entire block = (Surface area of the prism at the base - area of the top of the prism) + Lateral surface area of the pyramid
Surface area of the rectangular prism = 2(lb + bh + hl)
(here l, b, h are the length, width and height respectively)
= 2(5×5 + 5×4 + 4×5)
= 2(25 + 20 + 20)
= 2×65
= 130 cm²
Area of the top of the prism = (side)²
= 5²
= 25 cm²
Lateral area of the square pyramid = 4 × Area of one lateral side
= 4 × [tex][\frac{1}{2}(\text{Base})(\text{Height})][/tex]
= 4 × [tex][\frac{1}{2}(5)(6)][/tex]
= 60 cm²
Total paper required = (130 - 25) + 60
= 105 + 60
= 165 cm²
