Answer:
B
Step-by-step explanation:
Using the rule of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]
Given
[tex]\sqrt{6x^2}[/tex] × [tex]\sqrt{3x}[/tex]
= [tex]\sqrt{18x^3}[/tex]
= [tex]\sqrt{9(2)x^2(x)}[/tex]
= [tex]\sqrt{9}[/tex] × [tex]\sqrt{2}[/tex] × [tex]\sqrt{x^2}[/tex] × [tex]\sqrt{x}[/tex]
= 3 × [tex]\sqrt{2}[/tex] × x × [tex]\sqrt{x}[/tex]
= 3x × [tex]\sqrt{2}[/tex] × [tex]\sqrt{x}[/tex]
= 3x[tex]\sqrt{2x}[/tex] → B
