Question

Which is the graph of g(x) = 2x – 1 + 3? On a coordinate plane, an exponential function has a horizontal asymptote at y = 3 and crosses the y-axis at (0, 4). On a coordinate plane, an exponential function has a horizontal asymptote at y = negative 3 and crosses the y-axis at (0, negative 2) On a coordinate plane, an exponential function has a horizontal asymptote at y = negative 1 and crosses the y-axis at (0, 7). On a coordinate plane, an exponential function has a horizontal asymptote at y = negative 1 and crosses the y-axis at (0, negative 1).

Answer 1

The graph of g(x) is an exponential function that crosses the y-axis at y = 3.5, and a horizontal asymptote at y = 3.5

The function is given as:

$g(x) = 2^{x - 1} + 3$

Set x = 0, to calculate the y-intercept

$g(0) = 2^{0-1} + 3$

Simplify the exponent

$g(0) = 2^{-1} + 3$

Express 2^-1 as decimal

$g(0) =0.5 + 3$

Add 0.5 and 3

$g(0) =3.5$

This means that the graph of g(x) is an exponential function that crosses the y-axis at y = 3.5

Also, the graph of g(x) has a horizontal asymptote at y = 3.5

Read more about exponential graphs at:

https://brainly.com/question/8493280

Answer 2

Answer:

3 graph

Step-by-step explanation: