After selling tickets to a play, Jonah realizes that he has twice as many one dollar bills as he has five dollar bills, and he also has 6 less ten dollar bills as he has one dollar bills. If his total money with these bills is $237, how many five dollar bills does he have

Respuesta :

Answer:

He had 11 five dollar bills.

Step-by-step explanation:

Since Jonah realized that he had twice as many one dollar bills as he has five dollars bills, and 6 less ten dollar bills as he has one dollar bills, if we say that the number of one dollar bills he has is "x", then the number of five dollar bills and ten dollars bills will be:

five dollar bills = [tex]\frac{x}{2}[/tex]

ten dollar bills = [tex]x - 6[/tex]

Since the total money he had was [tex]237[/tex], then the sum of all the bills he had multiplied by it's respective values must be equal to that:

[tex]\text{(one dollar bills)} + 5*\text{(five dollar bills)} + 10*\text{(ten dollar bills)} = 237\\x + 5*\frac{x}{2} + 10*(x - 6) = 237\\x +\frac{5*x}{2} + 10*x - 60 = 237\\11*x + \frac{5*x}{2} = 237 + 60\\\frac{22*x + 5*x}{2} = 297\\27*x = 297*2\\x = \frac{594}{27} = 22[/tex]

Therefore he had 11 five dollar bills.