Question

On a coordinate plane, 2 exponential functions are shown. Function f (x) approaches y = 0 in quadrant 2 and increases into quadrant 1. Function g (x) approaches y = 0 in quadrant 1 and increases into quadrant 2.

Which function represents a reflection of f(x) = Three-eighths(4)x across the y-axis?


g(x) = NegativeThree-eighths (one-fourth) Superscript x

g(x) = Negative three-eighths(4)x

g(x) = Eight-thirds(4)-x

g(x) = Three-eighths(4)–x

Answer 1

Answer:

$g(x)=f(-x)=\frac{3}{8}(4)^{-x}$

Step-by-step explanation:

The pre-image is

$f(x)=\frac{3}{8}(4)^{x}$

To make a reflection across the y-axis, we need to apply the transformation

$(x,y) \implies (-x,y)$

Which give the function

$g(x)=f(-x)=\frac{3}{8}(4)^{-x}$

Therefore, the right answer is the last choice.

Answer 2

Answer:

D

Step-by-step explanation: