Question

The upper-left coordinates on a rectangle are (-8,8)(−8,8)left parenthesis, minus, 8, comma, 8, right parenthesis, and the upper-right coordinates are (-3,8)(−3,8)left parenthesis, minus, 3, comma, 8, right parenthesis. The rectangle has an area of 151515 square units.

Draw the rectangle on the coordinate plane below.

Answer 1

Answer:

The other two co-ordinates are (-3, 5) and (-8, 5).

Step-by-step explanation:

Consider the rectangle ABCD.

A = upper-left coordinates = (-8, 8)

B = upper-right coordinates = (-3, 8)

C = lower-left coordinates

D = lower-right coordinates

Let the side AB form the length of the rectangle.

Compute the distance between the points A and B as follows:

$AB=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

      $=\sqrt{(-3+8)^{2}+(8-8)^{2}}\\=\sqrt{(5)^{2}}\\=5$

The length of the rectangle ABCD is 5 units.

The are of ABCD is given as 15 square units.

Compute the breadth of the rectangle as follows:

$\text{Area}=\text{l}\times\text{b}\\15=5\times\text{b}\\b=3$

So, the breadth of the rectangle is 3 units.

Then from point B, 3 units below would be (-3, 5).

And from point A, 3 units below would be (-8, 5).

The rectangle on the coordinate plane is attached below.