Question

t(x) = ax^5 + 2 where is a real number. If the points (-2, 66) and (2, -62) are on the graph of the function classify as one of the following.

0 < a < 1
a < -1
a > 1
0 > a > -1

Answer 1

Answer:

a < -1

Step-by-step explanation:

Okay, so we are given this equation:

t(x) = ax^5 + 2

Lets plug in -2 as x and see what happens.. t(x) can be 66..

$a * (-2)^{5} + 2$ = 66

-32a + 2 = 66

-32a = 64

a = -2

A is less than -1,

a < -1