What is the y-coordinate of the point that divides the directed

line segment from J to K into a ratio of 2:3?

K(8,11)

J(-3,1)


*7

*-6

*5

*-5

Respuesta :

Answer:

(D)5

Step-by-step explanation:

Given the point J(-3,1) and K(8,11).

The line segment that divides the segment from J to K in any given ratio can be determined using the formula.

[tex]P(x,y)=\left(\dfrac{mx_2+nx_1}{m+n} ,\dfrac{my_2+ny_1}{m+n}\right)[/tex]

In the given case:

[tex](x_1,y_1)=(-3,1), (x_2,y_2)=(8,11)[/tex], m:n=2:3

Since we are to determine the y-coordinate of the point that divides JK into a ratio of 2:3, we have:

[tex]\dfrac{my_2+ny_1}{m+n}=\dfrac{2*11+3*1}{3+2}\\\\=\dfrac{22+3}{5}\\\\=\dfrac{25}{5}\\\\=5[/tex]

The y-coordinate of the point that divides the directed  line segment from J to K into a ratio of 2:3 is 5.

The correct option is D.

Answer:

The answer is actually C(5) not D

Step-by-step explanation: