Answer:
51.02m
Explanation:
KE = 1/2mv2
Where k.e = 250J
mass = 0.5 kg
g = 9.8 m/s2
250= 1/2×0.5×v^2
250= 0.5×0.5×v^2
250= 0.25v^2
v^2 = 250/0.25
v^2 = 1000
v =√1000
v = 31.62m/s
v^2= u^2-2gh........... (1)
Since the object will stop at it highest point, hence it final velocity there will be zero and since it is moving up against the gravity g= -9.8m/s^2. That was why the formula in equation 1 has a negative sign
From h = u^2/2g
Where v = 31.62m/s
g = 9.8m/s^2
H = (31.62m/s)^2/9.8×2
H= 1000/19.6
= 51.02m
Hence the height of it travelling will be
51.02m
