Question

a circle has a center located at 2 5 and passes through the point 10 3 answer
Determine the equation of the circle. Show how you arrived at your answer.
Write the equation of the tangent line to the circle at the point . Show how you determined your answer.

Answer 1

Answer:Explanation: The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. If a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.

Step-by-step explanation:

Answer 2

The circle equation has a center located at (2, 5) and passes through the point (10, 3) is (x - 2)² + (y - 5)² = 68

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

The circle has a center located at (2, 5) and passes through the point (10, 3), hence:

$Radius=\sqrt{(3-5)^2+(10-2)^2}=8.25$

The equation of the circle is:

(x-2)² + (y-5)² = 8.25²

(x - 2)² + (y - 5)² = 68

The circle equation has a center located at (2, 5) and passes through the point (10, 3) is (x - 2)² + (y - 5)² = 68

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