Question

what is x blank ×x to the power of 6 = x to the power of 9

Answer 1

$x^6=x^9\implies x^9-x^6=0\implies x^6(x^3-1)=0\implies x=0, x^3=1$. The values of $x$ that satisfy $x^3=1$ are $x=1, x=\frac{-1+i\sqrt{3}}{2}, x=\frac{-1-i\sqrt{3}}{2}$