raine divides three 2-ounce bags of rice into smaller bags. The first bag is divided into bags weighing 1/6-ounce each, and the third bag is divided into bags weighing 1/2- ounce each.

Raine divides three 2-ounce bags of rice into smaller bags. The first bag is divided into bags weighing 1/6-ounce each, the second bag is divided into bags weighing 1/3-ounce each and the third bag is divided into bags weighing 1/2- ounce each. Find the number of 1/6, 1/3 and 1/2 bags and graph it in a line plot.

1) How many bags weigh at least 1/6 of an ounce?

2) How many bags are more than 1/3 of an ounce?

3) What is the combined total of the 1/2 ounce bags?

4) What is the average weight of each of the bags?

Solution

Let the number of 1/6-ounce, 1/3-ounce and 1/2-ounce bags be x, y and z respectively.

(1/6) × x = 2

x = 2 × 6 = 12 bags of 1/6-ounce rice.

(1/3) × y = 2

y = 2 × 3 = 6 bags of 1/3 ounce of rice.

(1/2) × z = 2

z = 2 × 2 = 4 bags of 1/2-ounce rice.

The line plot is presented in the attached image to this answer.

1) All of the bags weigh at least 1/6 of an ounce. Hence, the number of bags that weigh more than 1/6 of an ounce = 12 + 6 + 4 = 22 bags

2) The bags that weigh more than 1/3 of an ounce are the 1/2-ounce bags, and there are only 4 of them. Hence, 4 bags weigh more than 1/3 of an ounce.

3) Combined total of the 1/2 ounce bags

= 4 bags × (1/2-ounce per bag) = 2 ounces.

4) The average weight of the bags is given as the sum total of the weight of the bags divided by the number of bags.

Total weight of the bags = [12 × (1/6)] + [6 × (1/3)] + [4 × (1/2)] = 2 + 2 + 2 = 6 ounces.

Total Number of bags = 12 + 6 + 4 = 22 bags

Average weight of the bags = (6/22) = (3/11) ounce per bag.

Hope this Helps!!!