Question

Jen bought 40 bracelets and 40 necklaces for $3,040. Mark bought 80 bracelets and 40 necklaces for $3,760.
Use elimination to sole the system of linear equations and determine how much each bracelet cost, x and how much each necklace coast. (x,y)

Answer 1

Answer:

• bracelet $18
• necklace $58

Step-by-step explanation:

You are given that ...

  40x +40y = 3040

  80x +40y = 3760

Eliminate y by subtracting the first equation from the second:

  (80x +40y) -(40x +40y) = (3760) -(3040)

  40x = 720

  x = 18

Using the first equation to find y, we have ...

  40y = 3040 -40x

  y = 76 -x . . . . . divide by 40

  y = 76 -18 = 58

The cost of a bracelet is $18; the cost of a necklace is $58.