Question

3.5 moles of argon gas are maintained at a temperature of 293K and a pressure of 2.5 atm. What is the volume
occupied by the argon gas sample? Value of R = 0.0821 L. atm/mol-K
A 33.7L
B 22.4L
C 31.2L
D 17.2L

Answer 1

Answer:

A 33.7L

Explanation:

Hello,

In this case, we can deal with argon as an ideal gas that can be studied via the ideal gas equation:

$PV=nRT$

Whereas we have the pressure, volume, moles, ideal gas constant and temperature respectively, so, for us to find the volume we simply solve for it as shown below:

$V=\frac{nRT}{P} =\frac{3.5mol*0.082\frac{atm*L}{mol*K} *293K}{2.5atm} \\\\V=33.7L$

Therefore, the answer is A 33.7L.

Best regards.