Question

The electric potential difference of a 125 F capacitor is measured across the terminals of the capacitor and found to be 9.0 V. The potential energy of the capacitor, rounded to two significant figures, is

Answer 1

Answer:

E=1/2CV^2

where E is potential energy, C is capacitance and V is the voltage.

E=1/2×125×9^2

E=1/2×125×81

E=5062.5

E=5100J to 2 significant figures.

Answer 2

Answer:

5.1

Explanation:

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