Respuesta :
Answer:
C. 6 ways
Step-by-step explanation:
When two fair dice are rolled, the sample space of the outcome is given below:
[tex](1,1) (1,2) (1,3) (1,4) (1,5) (1,6)\\(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)\\(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)\\(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)\\(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)\\(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)[/tex]
Where in the pair (x,y), x represents the red die and y represents the white die.
The outcome in which the sum of the two dice is less than 5 are:
[tex](1,1) (1,2) (1,3) \\(2,1) (2,2) \\(3,1)[/tex]
Therefore, this result can be obtained in 6 ways.
The correct option is C.
Considering all the possible outcomes, it is found that the number of times a sum of the two dice less than 5 can be obtained is:
C. 6 ways
What are the possible outcomes when two dices are rolled?
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
Of those, the ones with a sum of less than 5 are given by:
(1,1), (1,2), (1,3), (2,1), (2,2), (3,1)
6 ways, hence option C is correct.
A similar problem, in which the number of possible outcomes is found, is given at https://brainly.com/question/24314866
