Answer:
THE NEW VOLUME OF THE GAS SAMPLE IS 40 L AT 1 atm AND 400 K
Explanation:
Using general gas equation which combines Boyle's and Charles' law, the volume of the gas sample at the new pressure and temperature can be obtained.
P1V1/T1 = P2V2/T2
P1 = Initial pressure = 2 atm
V1 = Initial volume = 15 L
T1 = Initial temperature = 300 K
P2 = Final pressure = 1 atm
T2 = Final temperature = 400 K
V2 = Final volume = unknown
Substituting the values into the equation, we have;
V2 = P1V1T2 / P2 T1
V2 = 2 * 15 * 400 / 1 * 300
V2 = 12 000/ 300
V2 = 40 L
The new volume after the pressure was reduced to 1 atm and the temperature increased to 400 K is 40 L.
