Respuesta :
Answer:
601mmHg.
Explanation:
Step 1:
Data obtained from the question.
Initial pressure (P1) = 760mmHg
Initial temperature (T1) = 100°C = 100°C + 273 = 373K
Final temperature (T2) = 22°C = 22°C + 273 = 295K
Final pressure (P2) =..?
Step 2:
Determination of the new pressure at which the water will boil.
The new pressure on the at which the water will boil can be obtained as follow:
P1/T1 = P2/T2
760/373 = P2/295
Cross multiply to express in linear form
373 x P2 = 760 x 295
Divide both side by 373
P2 = (760 x 295) / 373
P2 = 601mmHg
Therefore, the new pressure at which the water will boil is approximately 601mmHg.