Question

Calculate the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L.

-7 C
11 C
15.5 C
288 C

Answer 1

Answer: $15.5^0C$

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 0.987 atm

V = Volume of gas = 12 L

n = number of moles = 0.50

R = gas constant =$0.0821Latm/Kmol$

T =temperature =  ?

$T=\frac{PV}{nR}$

$T=\frac{0.987atm\times 12L}{0.0820 L atm/K mol\times 0.50mol}=288.5K=(288.5-273)^0C=15.5^0C$

Thus the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L is $15.5^0C$