Answer:
Electrical force, F = 10.8 N
Explanation:
We have,
Charge 1, [tex]q_1=3\ \mu C=3\times 10^{-6}\ C[/tex]
Charge 2, [tex]q_2=4\ \mu C=4\times 10^{-6}\ C[/tex]
Distance between charges is 10 cm or 0.1 m
It is required find the electric force between two charges. The formula used to find the electrical force is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
k is electrostatic constant
Plugging all the values we get :
[tex]F=\dfrac{9\times 10^{9}\times 3\times 10^{-6}\times 4\times 10^{-6}}{(0.1)^2}\\\\F=10.8\ N[/tex]
So, the electrical force between charges is 10.8 N.
