Answer:
110L
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 44L
Initial temperature (T1) = 200K
Final temperature (T2) = 500K
Final volume (V2) =..?
The new volume of the balloon can be obtained by using Charles' law equation as shown below:
V1/T1 = V2/T2
44/200 = V2/500
Cross multiply
200 x V2 = 44 x 500
Divide both side by 200
V2 = 44 x 500/200
V2 = 110L
Therefore, the new volume of the balloon is 110L
