Question

Write the equation of a circle with a center at (-2, 3) and a radius of 4.

(x + 2)^2 + (y - 3)^2 = 4
(x - 2)^2 + (y + 3)^2 = 4
(x - 2)^2 + (y + 3)^2 = 16
(x + 2)^2 + (y - 3)^2 = 16

Answer 1

Answer:

The equation of a circle:

$(x+2)^2+(y-3)^2 = 16$

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2 = r^2$

(where the center is known as $(h,k)$ and the radius, known as $r$).

-Since you already have the center and the radius, use them for the equation of a circle:

Center: $(-2,3)$

Radius: $4$

$(x+2)^2+(y-3)^2 = 4^2$

After you have the equation of a circle, simplify the radius by the exponent $2$ :

$(x+2)^2+(y-3)^2 = 16$

So, you have found the equation of a circle.