Question

A sample of sugar (C12H22O11) contains
1.505 × 1023 molecules of sugar. How many moles of sugar are present in the sample? Answer without doing any calculations.

0.25 mol

0.50 mol

1.00 mol

2.50 mol

Answer 1

Answer:

0.25 mol

Explanation:

Use the formula n=N/NA

n= number of mols

N =  number of particles

Nᵃ = Avogadros constant = 6.02 x $\\10^{23$

So, n= $\frac{1.505 X 10^{23} }{6.02 X 10^{23}}$

The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.

Hope this helped :)