Respuesta :
Answer:
No real number solutions.
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 ( a ≠ 0 )
The discriminant is b² - 4ac
• If b² - 4ac > 0 the equation has 2 real and distinct roots
• If b² - 4ac = 0 the equation has 2 real and equal roots
• If b² - 4ac < 0 the equation has no real roots
Given
2x² + 4x + 8 = 0 ← in standard form
with a = 2, b = 4 and c = 8, then
b² - 4ac = 4² - (4 × 2 × 8) = 16 - 64 = - 48 , thus
The equation has no real number solutions because the discriminant is < 0