Respuesta :
Answer:
Base = 13in
Height = 17in
Step-by-step explanation:
Step-by-step explanation:
height of a parallelogram = 4 times more than it’s base
Let height = H
Base = B
H = 4 + B
area of the parallelogram = 221 in²
area of the parallelogram = base × height
221 = B × H = B × (4+B)
221 = 4B + B²
B² + 4B - 221 = 0
Using almighty formula to find B
See attachment for explanation
From the calculation:
Since the dimension of the parallelogram can't be negative, B = 13in
Height = B + 4 = 13+4
Height = 17in
Answer:
Base = 13 inches
Height = 17 inches
Step-by-step explanation:
The formula to find the area of a parallelogram = Base × Height
Let's represent Base = B
Height = H
From the question, the height is 4 times more than the Base
Height(H) = B + 4
Area = 221 square inches
Therefore, area of a parallelogram = Base × Height
221 sq in = B ×( B+4)
221 sq in = B² + 4B
B² + 4B - 221 = 0
We would solve the quadratic equation using factorisation method. Hence,
B² + 17B - 13B - 221 = 0
(B²+ 17B) - (13B - 221) = 0
B(B + 17) - 13(B + 17) = 0
(B + 17) (B - 13) = 0
B + 17 = 0
B = - 17
Or
B - 13 = 0
B = 13.
From the above calculation, since B = Base
B = -17 inches Or 13 inches
The base of a parallelogram cannot be negative, hence , The Base of the Parallelogram = 13 inches.
We are told that the height of the Parallelogram is 4 times more than the Base. This was represented but the equation
B + 4 = H
Since B = 13 :
13 + 4 = H
Height(H) = 17 inches.
Therefore, The base of the Parallelogram is 13 inches while the height of the Parallelogram is 17 inches.
