Respuesta :
Answer:
a is the correct answer in e2020
Step-by-step explanation:
Based on the calculations, the row operation (-2R₁ + R₂ → R₂) is equal to:[tex]\left[\begin{array}{cccc}3&12&8&102\\0&-6&-6&-42\\0&15&5&85\end{array}\right][/tex]
How to determine a row operation?
First of all, we would write a matrix to represent the number of tickets sold and the total cost of the tickets for three performances as follows:
[tex]\left[\begin{array}{cccc}3&12&8&102\\6&10&6&102\\0&15&5&85\end{array}\right][/tex]
Next, we would perform this row operation (-2R₁ + R₂ → R₂):
[tex]\left[\begin{array}{cccc}3&12&8&102\\(-2\times 3+6)&-2\times 12+18)&-2\times 6+6)&-2\times 102+162)\\0&15&5&85\end{array}\right][/tex]
Evaluating further, we have:
[tex]\left[\begin{array}{cccc}3&12&8&102\\0&-6&-6&-42\\0&15&5&85\end{array}\right][/tex]
Read more on matrix equation here: https://brainly.com/question/16980134
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Complete Question:
The drama club at a local high school sells adult, teen, and child tickets for a school play. The matrix below represents the tickets sold and the total cost of the tickets for three performances.
[tex]\left[\begin{array}{cccc}3&12&8&102\\0&-6&-6&-42\\0&15&5&85\end{array}\right][/tex]
What is the result of performing the row operation (-2R₁ + R₂ → R₂) on this matrix?