Answer:
[tex]y=2x-5[/tex]
Step-by-step explanation:
Slope Intercept is: [tex]y=mx+b[/tex]
'm' - slope
'b' - y-intercept
Slope is: [tex]m=\frac{\text{Rise}}{\text{Run}} =\frac{y_2-y_1}{x_2-x_1}[/tex]
We are given the points (3,1) and (1,-3).
[tex]m=\frac{-3-1}{1-3}=\frac{-4}{-2} =\frac{4}{2} =2[/tex]
The slope of the line is 2.
Therefore,
m = 2
We have the equation:
[tex]y=2x+b[/tex]
To find the y-intercept, we can substitute x and y for a point on the line.
I will use (3,1):
[tex]1=2(3)+b\\1=6+b\\1-6=6-6+b \leftarrow \text {Subtraction Property of Equality} \\\boxed {-5=b}[/tex]
The y-intercept is -5.
b = -5
The equation for the line given in the question is [tex]y=2x-5[/tex].