Question

Although electromagnetic waves can always be represented as either photons or waves, in the radio part of the spectrum we typically do not discuss photons (like we do in the visible) because they are at such a low energy. Nevertheless, they exist. Consider such a photon in a radio wave from an AM station has a 1545 kHz broadcast frequency.

Required:
What is the energy, in joules, of the photon?

Answer 1

Answer:

E = 1.02 x 10⁻²⁷ J

Explanation:

The energy of a photon is given by the Plank's formula. The formula is given as:

E = hυ

where,

E = Energy of Photon = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ J.s

υ = Frequency of the Wave = 1545 KHz = 1545000 Hz

Therefore, we can find the energy of photon in the given radio wave from an AM station, by substituting the known values in Plank's formula.

E = (6.626 x 10⁻³⁴ J.s)(1545000 Hz)

E = 1.02 x 10⁻²⁷ J

The energy of a photon, in a radio wave from an AM station has a 1545 kHz broadcast frequency, is found to be E = 1.02 x 10⁻²⁷ J

Answer 2

The energy , in joules, of the photon should be considered as the E = 1.02 x 10⁻²⁷ J.

Plank formula:

The energy of a photon should be like

E = hυ

where,

E = Energy of Photon = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ J.s

υ = Frequency of the Wave = 1545 KHz = 1545000 Hz

Now

E = (6.626 x 10⁻³⁴ J.s)(1545000 Hz)

E = 1.02 x 10⁻²⁷ J

hence, The energy , in joules, of the photon should be considered as the E = 1.02 x 10⁻²⁷ J.

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