A bond analyst is analyzing the interest rates for equivalent municipal bonds issued by two different states.
a) At α = 0.05, is there enough evidence to conclude that there is a difference in the interest rates paid by the two states?
State A:
Sample size 60
Mean interest rate (%) 3.2
Population variance .02
State B:
Sample size 60
Mean interest rate (%) 3.4
Population variance .05

Respuesta :

Answer:

[tex]z=\frac{(3.2-3.4)-0}{\sqrt{\frac{0.141^2}{60}+\frac{0.224^2}{60}}}}=-5.85[/tex]  

The p value can be calculated with this probability:

[tex]p_v =2*P(z<-5.85)=4.91x10^{-9}[/tex]  

The p value for this case is a value very low and near to 0 so then we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

Step-by-step explanation:

Information provided

[tex]\bar X_{1}=3.2[/tex] represent the mean for sample A

[tex]\bar X_{2}=3.4[/tex] represent the mean for sample B  

[tex]\sigma_{1}=\sqrt{0.02}= 0.141[/tex] represent the sample standard deviation for A

[tex]s_{2}=\sqrt{0.05}= 0.224[/tex] represent the sample standard deviation for B

[tex]n_{1}=60[/tex] sample size for the group A

[tex]n_{2}=60[/tex] sample size for the group B  

[tex]\alpha=0.05[/tex] Significance level provided

z would represent the statistic

Hypothesis to test

We want to verify if that there is a difference in the interest rates paid by the two states, the system of hypothesis would be:  

Null hypothesis:[tex]\mu_{1}-\mu_{2}=0[/tex]  

Alternative hypothesis:[tex]\mu_{1} - \mu_{2}\neq 0[/tex]  

The statistic for this case since we know the population deviations is given by:

[tex]z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}[/tex] (1)  

Replacing the info given we got:

[tex]z=\frac{(3.2-3.4)-0}{\sqrt{\frac{0.141^2}{60}+\frac{0.224^2}{60}}}}=-5.85[/tex]  

The p value can be calculated with this probability:

[tex]p_v =2*P(z<-5.85)=4.91x10^{-9}[/tex]  

The p value for this case is a value very low and near to 0 so then we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

ACCESS MORE
EDU ACCESS
Universidad de Mexico