Respuesta :
Answer:
[tex]y = -3x+11[/tex]
Step-by-step explanation:
I accept your challenge!
First we know that a equation of the line is a linear equation, and its equation is:
[tex]y = mx+b[/tex]
[tex]m: \text{slope}\\b: \text{y-intercept}[/tex]
In this context, the slope, defined as the steepness of a line is characterized as the ratio of RISE (the difference in the y-coordinates, the vertical change) over the RUN (the difference in x-coordinates, the horizontal change).
[tex]$m=\frac{\text{change in y}}{\text{change in x}}=\frac{\Delta y}{\Delta x}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} $[/tex]
Once we know two points where the line goes through, we can get the slope, once we know the change in y and x.
I will take [tex](3,2)[/tex] as Point 1 and [tex](4,-1)[/tex] as Point 2.
So, [tex]x_{1}=3 \text{ and } y_{1}=2\\x_{2}=4 \text{ and } y_{2}=-1[/tex]
[tex]$m=\frac{\text{change in y}}{\text{change in x}}=\frac{\Delta y}{\Delta x}=\frac{-1-2}{4-3} $[/tex]
[tex]$m=\frac{-3}{1}=-3 $[/tex]
Now we have to find the y-intercept:
To do so, think about the the points given and the nearly finished equation, we can find b with those two informations.
Our currently equation of the line is:
[tex]y = -3x+b[/tex]
Using the points, take Point 1 as an example, it says that when [tex]x = 3, y = 2[/tex], so plugging it in the equation:
[tex]2 = -3(3)+b\\2 = -9+b\\11 = b[/tex]
Taking the Point 2
[tex]-1 = -3(4)+b\\-1 = -12+b\\11 = b[/tex]
Now we found [tex]b[/tex]! The equation is complete!
[tex]y = -3x+11[/tex]