Answer:
(a) 165.46 V
(b) 7.78 A
Explanation:
(a) From the question,
Vrms = V₀/√2...................... Equation 1
Where V₀ = maximum potential difference across a lamp connected to the outlet.
make V₀ the subject of the equation.
V₀ = √2(Vrms)............... Equation 2
Given: Vrms = 117 V.
Substitute into equation 2
V₀ = (√2)(117)
V₀ = 165.46 V.
(b) Similarly,
I₀ = √2(Irms)....................... Equation 3
Given: Irms = 5.5 A
Substitute into equation 3
I₀ = (√2)(5.5)
I₀ = 7.78 A.
