Answer:
(B) -8
Step-by-step explanation:
Given the 2-column table below:
[tex]\left|\begin{array}{c|c}x&y\\--&--\\-3&14\\-1&10\\1&6\\4&0\\8&?\\10&-12\end{array}\right|[/tex]
Taking the pair (-3,14) and (-1,10)
[tex]Slope, m=\dfrac{10-14}{-1-(-3)} =\dfrac{-4}{2} =-2[/tex]
Taking the pair (1,6) and (4,0)
Slope, [tex]m=\dfrac{0-6}{4-1} =\dfrac{-6}{3} =-2[/tex]
Since the slope is constant, the table represents a linear function whose slope is -2. Therefore:
Taking the pair (8,y) and (4,0)
Slope, [tex]m=\dfrac{0-y}{4-8} =-2[/tex]
[tex]\dfrac{-y}{-4} =-2\\y=-2*4=-8[/tex]
Therefore, the value of ? on the y-column is -8.