Respuesta :
We can rewrite 27 as 9 × 3, where 9 is a perfect square, then take it through our steps. Since 3 doesn't have any perfect square factors, √(3) is as simplified as possible, so we have that the square root of 108 in radical form is 6 × √(3), or 6√(3).
Answer:
[tex]6\sqrt{3}[/tex]
Step-by-step explanation:
so we are going to create a factor tree which is the .The factor tree is any two numbers that equal to 108.
next we are going to pull out our pairs.so there are one pair of two's and one pair of threes
[tex]\sqrt[2]{108} =2*3\sqrt{3} =6\sqrt{3}[/tex]
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