Answer:
(2x -3)^2 = 0
Step-by-step explanation:
In this particular instance, the square is already complete. The rewrite is to show that.
(2x -3)^2 = 0
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In the general case, ...
(ax +b)^2 = a^2x^2 +2abx +b^2
Comparing this form to the given left-side expression, we see that ...
a = 2, b = -3
So, the trinomial is already a perfect square trinomial.
