Question

You have three pieces of paper in an envelope. One piece of paper has the number 1 written on it, another has the number 2 written on it, the other has the number 3 written on it. You draw and replace a piece of a paper three times. What is the probability that it’s in this order (1,2,3) or this order (2,2,2)?

Answer 1

Answer:

See below in bold.

Step-by-step explanation:

Prob( 1 is first drawn) = 1/3

Prob(2 is second) = 1/2

Prob(3 is 3rd) = 1/3

So probability of 1,2,3 is (1/3)^3 = 1/27.

(2,2,2) is the same probabiilty 1/27.