Question

Given the reaction: Ca(s) + Cu2+ (aq) - Ca2+(aq) + Cu(s)
What is the correct reduction half-reaction?​

Answer 1

Answer:

Cu2+ --> Cu (s)

Explanation:

Copper reduced from the oxidation state of +2 to 0.

Answer 2

The reduced specie is Cu^2+ and the reduction half equation is; Cu^2+(aq) + 2e ------> Cu(s)

What is a redox reaction?

The term redox reaction has to do with a reaction in which electrons are lost/ gained. As such one specie is reduced while the other is oxidized.

In this case, the reduced specie is Cu^2+ and the reduction half equation is; Cu^2+(aq) + 2e ------> Cu(s)

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