Question

a square and a triangle have equal perimeters. the square has a perimeter of 4(2p-4), and the triangle has a perimeter of 4p+36. find the perimeter value.

A. p= 72

B. p= 44

C. p= 88

D. p= 36

Answer 1

Answer:

C

Step-by-step explanation:

Since the figures have equal perimeters we can equate them, thus

4(2p - 4) = 4p + 36 ← distribute left side

8p - 16 = 4p + 36 ( subtract 4p from both sides )

4p - 16 = 36 ( add 16 to both sides )

4p = 52 ( divide both sides by 4 )

p = 13

Substitute p = 13 into either of the 2 expressions, then

4p + 36 = 4(13) + 36 = 52 + 38 = 88 → C