Answer:
see explanation
Step-by-step explanation:
Using the tangent and sine ratios in the right triangle EFG
tan60° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{FG}{EG}[/tex] = [tex]\frac{28}{EG}[/tex] ( multiply both sides by EG )
EG × tan60° = 28 ( divide both sides by tan60° )
EG = [tex]\frac{28}{tan60}[/tex] ≈ 16.2 in ( to the nearest tenth )
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sin60° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{FG}{EF}[/tex] = [tex]\frac{28}{EF}[/tex] ( multiply both sides by EF )
EF × sin60° = 28 ( divide both sides by sin60° )
EF = [tex]\frac{28}{sin60}[/tex] ≈ 32.3 in ( to the nearest tenth )
