Use the Change of Base Formula to evaluate log3 58. Then convert log3 58 to a logarithm in base 4. Round to the nearest thousandth.

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caylus
Hello,

[tex]log_3(58)= \dfrac{ln(58)}{ln(3)}=3,69597450... \\ log_3(58)=log_4(x)\\ \dfrac{ln(58)}{ln(3)} = \dfrac{ln(x)}{4}==\textgreater\ x=e^{ \frac{ln(58)*ln(4)}{ln(3)}}\\ =167,957104437222249066099... [/tex]

≈167.96

Answer:

[tex]\log_358\approx 3.696[/tex]

[tex]\Rightarrow \dfrac{\log_458}{\log_43}[/tex]

Step-by-step explanation:

Given: [tex]\log_358[/tex]

We need to re-write the log expression with base 4 using base change property of log.

Log property:

[tex]\log_ab=\dfrac{\log_cb}{\log_ca}[/tex]

Evaluate:

[tex]\Rightarrow \log_358[/tex]

[tex]\Rightarrow \dfrac{\log58}{\log3}[/tex]

[tex]\Rightarrow \dfrac{1.763427}{0.47712}\approx 3.696[/tex]

Convert with base 4:

[tex]\Rightarrow \log_358[/tex]

[tex]\Rightarrow \dfrac{\log_458}{\log_43}[/tex]

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