Respuesta :
Hello,
[tex]log_3(58)= \dfrac{ln(58)}{ln(3)}=3,69597450... \\ log_3(58)=log_4(x)\\ \dfrac{ln(58)}{ln(3)} = \dfrac{ln(x)}{4}==\textgreater\ x=e^{ \frac{ln(58)*ln(4)}{ln(3)}}\\ =167,957104437222249066099... [/tex]
≈167.96
[tex]log_3(58)= \dfrac{ln(58)}{ln(3)}=3,69597450... \\ log_3(58)=log_4(x)\\ \dfrac{ln(58)}{ln(3)} = \dfrac{ln(x)}{4}==\textgreater\ x=e^{ \frac{ln(58)*ln(4)}{ln(3)}}\\ =167,957104437222249066099... [/tex]
≈167.96
Answer:
[tex]\log_358\approx 3.696[/tex]
[tex]\Rightarrow \dfrac{\log_458}{\log_43}[/tex]
Step-by-step explanation:
Given: [tex]\log_358[/tex]
We need to re-write the log expression with base 4 using base change property of log.
Log property:
[tex]\log_ab=\dfrac{\log_cb}{\log_ca}[/tex]
Evaluate:
[tex]\Rightarrow \log_358[/tex]
[tex]\Rightarrow \dfrac{\log58}{\log3}[/tex]
[tex]\Rightarrow \dfrac{1.763427}{0.47712}\approx 3.696[/tex]
Convert with base 4:
[tex]\Rightarrow \log_358[/tex]
[tex]\Rightarrow \dfrac{\log_458}{\log_43}[/tex]