Question

Find two consecutive odd integers such that the sum of their squares is 202.

Answer 1

Answer:

9 and 11

Step-by-step explanation:

The squareroot of 202 is 14... so the numbers are both less than 14.

9*9= 81

11*11= 121

121+81= 202

Answer 2

Answer:

9 and 11

Step-by-step explanation:

(9^2) + (11^2) Simplify the exponents

81 + 121 = 202