Answer:
Height of the mountain was 28331.8 feet.
Step-by-step explanation:
An observer took the measurements from two sights C and D.
Point D was 1000 ft away from the earlier sight point C.
Angle of elevations from points C and D were 85° and 83° respectively.
From ΔABC,
tan85 = [tex]\frac{h}{x}[/tex]
x = [tex]\frac{h}{tan85}[/tex] -----(1)
Similarly, from ΔABD,
tan83 = [tex]\frac{h}{(x+1000)}[/tex]
x + 1000 = [tex]\frac{h}{tan83}[/tex]
x = [tex]\frac{h}{tan83}-1000[/tex] -----(2)
Now we substitute the value of x from equation (1) in the equation (2)
[tex]\frac{h}{tan85}=\frac{h}{tan83}-1000[/tex]
0.122785h - 0.087488h = 1000
0.035296h = 1000
h = 28331.822 ft
h ≈ 28331.8 ft
Therefore, height of the mountain was 28331.8 feet.