Question

Find the 66th term in the following
arithmetic sequence :
--92, -85, -78, -71, ...

Answer 1

Answer:

363

Step-by-step explanation:

The n th term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 92 and d = - 85 - (- 92) = - 85 + 92 = 7 , thus

$a_{66}$ = - 92 + (65 × 7) = - 92 + 455 = 363

Answer 2

Answer:

363.

Step-by-step explanation:

We see that each term increases by 7.

This is an arithmetic sequence with first term (a1) = -92  and the common difference (d) is 7.

an = a1 + (n - 1)d

a66 = -92 + (66 - 1)7

= -92 + 455

= 363.