Answer:
Step-by-step explanation:
[tex]\frac{1}{4}x-\frac{1}{8}=\frac{7}{8}+\frac{1}{2}\\\\\frac{1}{4}x=\frac{7}{8}+\frac{1}{2}+\frac{1}{8}\\\\\frac{1}{4}x=\frac{7}{8}+\frac{1}{8}+\frac{1}{2}\\\\\frac{1}{4}x=\frac{7+1}{8}+\frac{1}{2}\\\\\frac{1}{4}x=\frac{8}{8}+\frac{1}{2}\\\\\frac{1}{4}x=1+\frac{1}{2}\\\\\frac{1}{4}x=\frac{2}{2}+\frac{1}{2}\\\\\frac{1}{4}x=\frac{2+1}{2}\\\\\frac{1}{4}x=\frac{3}{2}\\\\x=\frac{3}{2}*\frac{4}{1}\\\\x=3*2\\\\x=6[/tex]
