Respuesta :

Answer: 220

Step-by-step explanation:

When we wanto to create a group of K elements for a set of N elements (where the order of the K elements does not matter, so we do not considerate the permutations of the K elements), the number of possible combinations is:

[tex]C = \frac{N!}{(N - K)!*K!}[/tex]

Here N = 12 and K = 3

[tex]C = \frac{12!}{9!*3!} = \frac{12*11*10}{3*2} = 220[/tex]

So there are 220 possible combinations

Answer:

220

Step-by-step explanation:

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