Respuesta :
Answer: 220
Step-by-step explanation:
When we wanto to create a group of K elements for a set of N elements (where the order of the K elements does not matter, so we do not considerate the permutations of the K elements), the number of possible combinations is:
[tex]C = \frac{N!}{(N - K)!*K!}[/tex]
Here N = 12 and K = 3
[tex]C = \frac{12!}{9!*3!} = \frac{12*11*10}{3*2} = 220[/tex]
So there are 220 possible combinations