Question

Help needed asap in 10 mins please ​

Answer 1

Answer:

C

Step-by-step explanation:

You can use elimination by plugging in choices, by the time I get to C you know that 2/1+3/3=3 and that 3/1+6/3=5

Answer 2

Answer:

The answer is C.

Step-by-step explanation:

First you have to solve this simultaneous equation by substitution :

$\frac{2}{x} + \frac{3}{y} = 3 - - - (1)$

$\frac{3}{x} + \frac{6}{y} = 5 - - - (2)$

Next you can make any variable as a subject. So I will choose to make x the subject in (1) :

$\frac{2}{x} + \frac{3}{y} = 3$

$\frac{2}{x} = 3 - \frac{3}{y}$

$\frac{2}{x} = \frac{3y - 3}{y}$

$x(3y - 3) = 2y$

$x = \frac{2y}{3y - 3} - - - (3)$

Lastly, you can solve the equations :

$(3)→(2)$

$(3 \div \frac{2y}{3y - 3}) + \frac{6}{y} = 5$

$(3 \times \frac{3y - 3}{2y}) + \frac{6}{y} = 5$

$\frac{9y - 9}{2y} - \frac{6}{y} = 5$

$\frac{9y - 9 + 6(2)}{2y} = 5$

$\frac{9y - 9 + 12}{2y} = 5$

$\frac{9y + 3}{2y} = 5$

$9y + 3 = 5(2y)$

$9y + 3 = 10y$

$y = 3$

$substitute \: y = 3 \: into \: (1)$

$x = \frac{2y}{3y - 3}$

$x = \frac{2(3)}{3(3) - 3}$

$x = \frac{6}{9 - 3}$

$x = \frac{6}{3}$

$x = 2$